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IBM C2090-303 Exam Syllabus Topics:
| Section | Objectives |
|---|---|
| Topic 1: Stages and Transformations | - Common stages (Transformer, Lookup, Join, Aggregator) - Data transformation and mapping techniques |
| Topic 2: Job Design and Development | - Job sequences and control flow - Designing server and parallel jobs |
| Topic 3: DataStage Fundamentals | - Parallel processing concepts and framework - Architecture and components of IBM InfoSphere DataStage |
| Topic 4: Administration and Deployment | - Project deployment and environment management - Monitoring and troubleshooting DataStage jobs |
| Topic 5: Data Integration and Quality | - Handling heterogeneous data sources - Data cleansing and validation concepts |
| Topic 6: Performance Tuning and Optimization | - Parallel job performance tuning techniques - Resource management and optimization strategies |
IBM InfoSphere DataStage v9.1 Sample Questions:
A job using a one-node configuration file writes to a target Sequential File stage. The target Sequential File stage has been set to write to three different sequential files. How many instances of the Sequential File stage will run in parallel?
- A. The job will abort, because a configuration file with at least three nodes is required.
- B. Three.
- C. One.
- D. Two.
Correct Answer: B 🗳️
A job design consists of an input Row Generator stage, a Filter stage, followed by a Transformer stage and an output Sequential File stage. The job is run on an SMP machine with a configuration file defined with three nodes. The $APT_DISABLE_COMBINATION variable is set to True. How many player processes will this job generate?
- A. 12
- B. 10
- C. 16
- D. 8
Correct Answer: D 🗳️
You would like to run a particular processing job within a job sequence for each weekday. What two methods could be used? (Choose two.)
- A. Add the job scheduler stage to the job sequence and set to weekdays only.
- B. Have a parameter set that contains the days of the week you would like to process and routine to parse the days of the week contained in the "day" parameter.
- C. Call a routine in the job sequencer that starts the processing job for each day you would like to process.
- D. Start Loop and End Loop activity stages on the job sequencer canvas where you loop through the days and pass a value for each day into the job via parameter.
- E. Set the frequency property in the job scheduler to weekdays only.
Correct Answer: C,D 🗳️
A job design consists of an input Sequential Files stage, a Sort stage, followed by a Transformer stage and an output Sequential File stage. In the input Sequential Files stage, the "Number of readers per node" property has been set to 3. The job is run on an SMP machine with a configuration file defined with 3 nodes. The $APT_DISABLE_COMBINATION variable is set to True. How many player processes will this job generate?
- A. 12
- B. 10
- C. 6
- D. 8
Correct Answer: D 🗳️
Rows of data going into a Transformer stage are sorted and hash partitioned by the Input.Product column. Using stage variables, how can you determine when a new row is the first of a new group of Product rows?
- A. Create a stage variable named sv_IsNewProduct and follow it by a second stage variable
named sv_Product. Map the Input.Product column to
sv_Product. The derivation for sv_IsNewProduct is: IF Input.Product = sv_Product THEN "YES"
ELSE "NO". - B. Create a stage variable named sv_Product and follow it by a second stage variable named
sv_IsNewProduct. Map the Input.Product column to
sv_Product. The derivation for sv_IsNewProduct is: IF Input.Product <> sv_Product THEN "YES"
ELSE "NO". - C. Create a stage variable named sv_IsNewProduct and follow it by a second stage variable
named sv_Product. Map the Input.Product column to
sv_Product. The derivation for sv_IsNewProduct is: IF Input.Product <> sv_Product THEN "YES"
ELSE "NO". - D. Create a stage variable named sv_Product and follow it by a second stage variable named
sv_IsNewProduct. Map the Input.Product column to
sv_Product. The derivation for sv_IsNewProduct is: IF Input.Product = sv_Product THEN "YES"
ELSE "NO".
Correct Answer: C 🗳️
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